How much part of an atom occupies each corner of bcc unit cell?
How much part of an atom occupies each corner of bcc unit cell?
- $1 / 4$
- $1 / 8$
- $1 / 2$
- $1 / 6$
Solution
A BCC unit cell contains two atoms: one-eighth of an atom at each of the eight corners (8x18=1 atom from the corners) plus one atom from the center
Asked in: MHT CET 2020 (19 Oct Shift 1)
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