How many total voids are present in 1 mole of compound that forms hcp structure?
How many total voids are present in 1 mole of compound that forms hcp structure?
$1.806 \times 10^{24}$
$1.204 \times 10^{24}$
$3.011 \times 10^{23}$
$6.022 \times 10^{23}$
Solution
In HCP structure
For each atom total three voids are present (one octahedral and two tetrahedral) Number of atoms in $1 \mathrm{~mol}$ of compound $=6.022 \times 10^{23}$
Total number of voids $=$ No. of atoms $\times 3$
$\begin{aligned}
& =6.022 \times 10^{23} \times 23 \\
& =18.06 \times 10^{23} \\
& =1.806 \times 10^{24}
\end{aligned}$