How many tetrahedral voids are present in 0.4 mole of a compound that forms hcp structure?
How many tetrahedral voids are present in 0.4 mole of a compound that forms hcp structure?
$4.8 \times 10^{23}$
$3.011 \times 10^{23}$
$1.2 \times 10^{23}$
$2.4 \times 10^{23}$
Solution
In HCP structure for each atom one octahedral void and two tetrahedral voids will be present.
No. of atoms $=0.4 \times \mathrm{N}_{\mathrm{A}}=0.4 \times 6.022 \times 10^{23}$
No. of tetrahedral voids $=$ No. of atoms $\times 2$
$\begin{aligned}
& =0.4 \times 6.022 \times 10^{23} \times 2 \\
& =4.8 \times 10^{23}
\end{aligned}$