How many possible values of $(p + q + r)$ are there satisfying $\dfrac{1}{p} + \dfrac{1}{q} + \dfrac{1}{r} =…

How many possible values of $(p + q + r)$ are there satisfying $\dfrac{1}{p} + \dfrac{1}{q} + \dfrac{1}{r} = 1$, where $p$, $q$ and $r$ are natural numbers (not necessarily distinct)?
  1. None
  2. One
  3. Three
  4. More than three

Solution

The natural-number solutions of $\dfrac{1}{p}+\dfrac{1}{q}+\dfrac{1}{r}=1$ (unordered) are: $(2,3,6)$ giving sum 11, $(2,4,4)$ giving sum 10, and $(3,3,3)$ giving sum 9. These yield three distinct values of $(p+q+r)$: 9, 10 and 11. Hence the answer is three.

Asked in: CSAT 2025

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