How many moles of nitrogen atoms are present in $8 \mathrm{~g}$ of ammonium nitrate?
How many moles of nitrogen atoms are present in $8 \mathrm{~g}$ of ammonium nitrate?
- $0.1 \mathrm{~mol}$
- $0.2 \mathrm{~mol}$
- $0.4 \mathrm{~mol}$
- $0.8 \mathrm{~mol}$
Solution
Chemical formula of ammonium nitrate is
$\begin{array}{ll}
& \mathrm{NH}_4 \mathrm{NO}_3 . \\
& 1 \mathrm{~mol} \mathrm{NH}_4 \mathrm{NO}_3 \equiv 2 \mathrm{~mol} \mathrm{~N} \text {-atoms } \\
\therefore \quad & 80 \mathrm{~g} \mathrm{NH}_4 \mathrm{NO}_3^{-}=2 \mathrm{~mol} \mathrm{~N} \text {-atoms } \\
\therefore \quad & 8 \mathrm{~g} \mathrm{NH}_4 \mathrm{NO}_3=0.2 \mathrm{~mol} \mathrm{~N} \text {-atoms }
\end{array}$
Asked in: MHT CET 2023 (10 May Shift 2)
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