How many moles of electrons are required for the reduction of 3 mole ions of $\mathrm{Zn}^{2+}$ to…

How many moles of electrons are required for the reduction of 3 mole ions of $\mathrm{Zn}^{2+}$ to $\mathrm{Zn}(\mathrm{s})$ ?
  1. 9
  2. 6
  3. 2
  4. 3

Solution

$\begin{aligned} & \underset{1 \mathrm{~mol}}{\mathrm{Zn}^{+2}+2 \mathrm{e}^{-} \rightarrow \mathrm{Zn}(\mathrm{s})} \\ & \therefore 3 \mathrm{~mol} \times 2 = 6 \mathrm{~mol} \end{aligned}$

Asked in: MHT CET 2022 (07 Aug Shift 1)

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