How many moles of carbon atoms are present in 3.6 kg of carbon?

How many moles of carbon atoms are present in 3.6 kg of carbon?
  1. $3.0 \times 10^2$ mole
  2. $1.8 \times 10^2$ mole
  3. $2.4 \times 10^2$ mole
  4. $4.8 \times 10^2$ mole

Solution

$\begin{aligned} & 3.6 \mathrm{~kg} \text { of carbon }=3600 \mathrm{~g} \\ & 12 \mathrm{~g} \mathrm{C}=1 \text { mole C-atoms } \\ \therefore \quad & 3600 \mathrm{~g} \mathrm{C}=\frac{3600 \mathrm{~g} \times 1 \mathrm{~mol}}{12 \mathrm{~g}} \\ = & 3.0 \times 10^2 \text { mole C-atoms }\end{aligned}$

Asked in: MHT CET 2024 (02 May Shift 2)

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