How many molecules of carbon dioxide are formed when 0.6 g carbon is burnt in air?

How many molecules of carbon dioxide are formed when 0.6 g carbon is burnt in air?
  1. $3.01 \times 10^{22}$
  2. $2.01 \times 10^{23}$
  3. $6.02 \times 10^{22}$
  4. $5.02 \times 10^{23}$

Solution


$\begin{aligned} \therefore \quad & 12 \mathrm{~g} \text { of } \mathrm{C} \text { will give } 44 \mathrm{~g} \text { of } \mathrm{CO}_2 \\ & 0.6 \mathrm{~g} \text { of } \mathrm{C} \text { will give } \\ & =\frac{44 \times 0.6}{12}=2.2 \mathrm{~g} \text { of } \mathrm{CO}_2 \\ & \text { Number of } \mathrm{CO}_2 \text { molecules } \\ & =\frac{2.2 \times 6.023 \times 10^{23}}{44}=3.01 \times 10^{22}\end{aligned}$

Asked in: MHT CET 2024 (11 May Shift 2)

Practice more Some Basic Concepts of Chemistry questions on Aicharya