How many grams of concentrated nitric acid solution should be used to prepare $250 \mathrm{~mL}$ of $2.0…
- $90.0 \mathrm{~g}$ conc. $\mathrm{HNO}_{3}$
- $70.0 \mathrm{~g}$ conc. $\mathrm{HNO}_{3}$
- $54.0 \mathrm{~g}$ conc. $\mathrm{HNO}_{3}$
- $45.0 \mathrm{~g}$ conc. $\mathrm{HNO}_{3}$
Solution
$2=\frac{\text { wt. }}{63} \times \frac{1000}{250}$
$\mathrm{wt}=\frac{63}{2} \mathrm{~g}$
wt. of $70 \%$ acid $=\frac{100}{70} \times 31.5=45 \mathrm{~g}$
Asked in: JEE-TOPICTESTS-CHEMISTRY