How many gram of dihydrogen is required to react with dinitrogen to produce $34 \mathrm{~g}$ of ammonia?
How many gram of dihydrogen is required to react with dinitrogen to produce $34 \mathrm{~g}$ of ammonia?
- $6 \mathrm{~g}$
- $2 \mathrm{~g}$
- $12 \mathrm{~g}$
- $3 \mathrm{~g}$
Solution
$N_{2}(g) + 3H_{2}(g) →2NH_{3}(g)$
$(28~g)\quad \quad (6~g) \quad \quad \quad(34~g)$
$28~g$ of $N_2$ reacts with $6~g$ of $H_2$.
Asked in: MHT CET 2020 (20 Oct Shift 2)
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