How many geometrical isomers are possible for the following compounds:
$3-$Bromo$-5-$iodo methylcyclohexane

Question

How many geometrical isomers are possible for the following compounds: $3-$Bromo$-5-$iodo methylcyclohexane

Aicharya · Accepted Answer

Four geometrical isomers:
(I)

cis$-3-$Bromo-cis$-5-$iodo-methyl cyclohexane
(All cis)
(II)

cis$-3-$Bromo-trans$-5-$ iodo-methyl cyclohexane
$(\mathrm{Me}, \mathrm{Br} \Rightarrow$ cis $; \mathrm{Me}, \mathrm{I} \Rightarrow$ trans $)$
(III)

trans$-3-$Bromo-cis$-5-$iodo methyl cyclohexane
$(\mathrm{Me}, \mathrm{Br}=$ trans; $\mathrm{Me}, \mathrm{I}=c i s)$
(IV)

trans$-3-$Bromo-trans$-5-$iodo-methyl cyclohexane
($\mathrm{Me}$, $\mathrm{Br} \Rightarrow$ trans; $\mathrm{Me}, \mathrm{I} \Rightarrow$ trans $)$ .

Solution