How many electrons are involved in the reaction when $0 \cdot 40$ F of electricity is passed through an…
How many electrons are involved in the reaction when $0 \cdot 40$ F of electricity is passed through an electrolytic solution?
- $6.642 \times 10^{25}$
- $2.4088 \times 10^{23}$
- $1.505 \times 10^{24}$
- $6.022 \times 10^{23}$
Solution
$\begin{array}{l}
1 \mathrm{~F}=96500 \mathrm{C} \\
\therefore \quad 0.4 \mathrm{~F}=96500 \times 0.4=38600 \mathrm{C}
\end{array}$
$\begin{aligned}
\text { Now, } 96500 \mathrm{C} &=6.022 \times 10^{23} \text { electrons } \\
\therefore 38600 \mathrm{C} &=\frac{6.022 \times 10^{23} \times 38600}{96500} \\
&=2.4088 \times 10^{23} \text { electrons }
\end{aligned}$
Asked in: MHT CET 2020 (16 Oct Shift 1)
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