How many distinct alkenes obtained from the 3-Bromo3-methylhexane upon treatment with alc. $\mathrm{KOH}$ ?
- $2$
- $3$
- $4$
- $5$
Solution

3 different alkenes obtained 3-Bromo-3-methylhexane As there are three distinct $\beta$-hydrogens (on $\beta$-carbons), we can get three different alkenes.
Asked in: AP EAMCET 2023 (19 May Shift 1)