How many 3-digit natural numbers (without repetition of digits) are there such that each digit is odd and…

How many 3-digit natural numbers (without repetition of digits) are there such that each digit is odd and the number is divisible by 5?
  1. 8
  2. 12
  3. 16
  4. 24

Solution

All digits are odd and distinct, so digits come from {1, 3, 5, 7, 9}. Divisible by 5 means the units digit is 5. The first two places can be filled from the remaining 4 odd digits in $4 \times 3 = 12$ ways.

Asked in: CSAT 2022

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