How long a current of 3 amperes has to be passed through a solution of $\mathrm{AgNO}_{3}$ to coat a metal…
- $125.1$ seconds
- $12.5$ seconds
- $155.2$ seconds
- 200 seconds
Solution
Mass $=$ Volume $\times$ density
$\therefore$ Mass of $\mathrm{Ag}$ to be deposited
$=\frac{80 \times 0.005}{10} \times 10.5=0.42 \mathrm{~g}$
Amount deposited $=\frac{i \times t \times E . w t}{96500}$
$\therefore 0.42=\frac{108 \times 3 \times \mathrm{t}}{98500} \therefore \mathrm{t}=125.1$ seconds
Asked in: JEE-TOPICTESTS-CHEMISTRY