How fast is an electron moving if it has a wavelength equal to the distance it travels in one second?
- $\sqrt{\frac{\mathrm{h}}{\mathrm{m}}}$
- $\sqrt{\frac{m}{h}}$
- $\sqrt{\frac{h}{p}}$
- $\sqrt{\frac{\mathrm{h}}{2(\mathrm{KE})}}$
Solution
$\therefore \quad \lambda \mathrm{v}=\mathrm{v}^{2}=\frac{\mathrm{h}}{\mathrm{m}}$
$\therefore \quad \mathrm{v}=\sqrt{\frac{\mathrm{h}}{\mathrm{m}}}$ ~
Asked in: JEE-TOPICTESTS-CHEMISTRY