Hex- 4 -ene- 2 -ol on treatment with PCC gives ' A '. ' A ' on reaction with sodium…

Hex-4-ene-2-ol on treatment with PCC gives 'A'. 'A' on reaction with sodium hypoiodite gives 'B', which on further heating with soda lime gives 'C'. The compound 'C' is
  1. 2-pentene
  2. proponaldehyde
  3. 2-butene
  4. 4-methylpent-2-ene

Solution

Hex-4-ene-2-ol on reaction with PCC forms Hex-4-ene-2-one.

Hex-4-ene-2-one on iodoform reaction gives pent-2 enoic acid and iodoform.

Pent-2 enoic acid on decarboxylation with soda lime forms but-2-ene. 

Asked in: JEE Main 2022 (24 Jun Shift 2)

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