$\mathrm{C}_2 \mathrm{H}_5 \mathrm{Br} \stackrel{\mathrm{AgCN}}{\longrightarrow} \mathrm{X}…
$\mathrm{C}_2 \mathrm{H}_5 \mathrm{Br} \stackrel{\mathrm{AgCN}}{\longrightarrow} \mathrm{X} \underset{\mathrm{Zn}-\mathrm{Rg} / \mathrm{HCl}}{\stackrel{\text { Reduction }}{\longrightarrow}} \mathrm{Y}$, Here $\mathrm{Y}$ is
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Ethyl methyl amine
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n-propylamine
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Isopropylamine
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Ethylamine
Asked in: JEE Main 2012 (07 May Online)
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