Hemispherical bowl, radius $7$ cm. Volume of water it can hold (use $\pi=22/7$) is
Hemispherical bowl, radius $7$ cm. Volume of water it can hold (use $\pi=22/7$) is
- approx $718.67$ cm³
- $308$ cm³
- $1437$ cm³
- $616$ cm³
Solution
$(2/3)(22/7)(343)\approx 718.67$.
Asked in: MH-SSC-9
Practice more Surface Area and Volume questions on Aicharya