Heating of diborane with excess of ammonia to a high temperature yields

Question

Aicharya · Accepted Answer

When diborane is heated with excess ammonia, it reacts with ammonia to form borazine and hydrogen.
"This reaction takes place at a high temperature of $180-190^{\circ} \mathrm{C}^{\prime \prime}$. This reaction of diborane and ammonia is considered to be highly complex in nature. Diborane is majorly used as rocket propellants and also as a reducing agent.
The chemical equation for the reaction is:
$\mathrm{B}_{2} \mathrm{H}_{6}+\mathrm{NH}_{3} ightarrow \mathrm{B}_{3} \mathrm{N}_{3} \mathrm{H}_{6}+\mathrm{H}_{2}$
The balanced equation for the reaction is:
$3 \mathrm{B}_{2} \mathrm{H}_{6}+6 \mathrm{NH}_{3} ightarrow 2 \mathrm{B}_{3} \mathrm{N}_{3} \mathrm{H}_{6}+12 \mathrm{H}_{2}$ ~

Heating of diborane with excess of ammonia to a high temperature yields

Solution