Heating of 2-chloro-1-phenylbutane with E t O K / E t O H gives X as the major product. Reaction X with H g ( O A c ) 2 / H 2 O followed by N a B H 4 gives Y as the major product. Y is:

Question

Aicharya · Accepted Answer

EtOK is potassium ethylene oxide and it is colourless gas and is liquid at low temperatures and is highly flammable i.e. that catches fire easily and undergoes alkylation reactions with many organic compounds and EtOH is the ethanol.

The heating of 2-chloro-1-phenylbutane with $EtOK / EtOH$ gives X as the major product. Reaction X with H $g {(OAc)}_{2} / H_{2} O$ followed by ${NaBH}_{4}$ gives Y as the major product. Y is 1-phenylbutanol.

Heating of 2-chloro-1-phenylbutane with E t O K / E t O H gives X as the major product. Reaction X with H g…

Solution