Heat treatment of muscular pain involves radiation of wavelength of about 900 nm. Which spectral line of H…

Heat treatment of muscular pain involves radiation of wavelength of about 900 nm. Which spectral line of H atom is suitable for this?
Given : Rydberg constant $\mathrm{R}_{\mathrm{H}}=10^5 \mathrm{~cm}^{-1},$ $\mathrm{~h}=6.6 \times 10^{-34} \mathrm{~J} \mathrm{~s},$ $\mathrm{c}=3 \times 10^8 \mathrm{~m} / \mathrm{s}$
  1. Balmer series, $\infty \rightarrow 2$
  2. Lyman series, $\infty \rightarrow 1$
  3. Paschen series, $\infty \rightarrow 3$
  4. Paschen series, $5 \rightarrow 3$

Solution

$\begin{aligned}
& \lambda=900 \mathrm{~nm} \quad \text { H-atom }(\mathrm{Z}=1) \\
& =9 \times 10^{-5} \mathrm{~cm} \\
& \mathrm{R}_{\mathrm{H}}=10^5 \mathrm{~cm}^{-1} \\
& \text { Ryderg eq. }=\frac{1}{\lambda}=\mathrm{R}_{\mathrm{H}} \mathrm{Z}^2 \times\left(\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right) \\
& \Rightarrow \frac{1}{\lambda \times \mathrm{R}_{\mathrm{H}}}=\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2} \\
& \Rightarrow \frac{1}{9 \times 10^{-5} \mathrm{~cm} \times 10^5 \mathrm{~cm}^{-1}}=\left(\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}\right) \\
& \Rightarrow \frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}=\frac{1}{9}
\end{aligned}$
It is possible when $\mathrm{n}_1=3, \mathrm{n}_2=\infty$
Possible series : $\infty \rightarrow 3$

Asked in: JEE Main 2025 (23 Jan Shift 1)

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