Heat energy of 735   J is given to a diatomic gas allowing the gas to expand at constant pressure. Each gas molecule rotates around an internal axis but do not oscillate. The increase in the internal energy of the gas will be:

Question

Heat energy of 735 &#160; J is given to a diatomic gas allowing the gas to expand at constant pressure. Each gas molecule rotates around an internal axis but do not oscillate. The increase in the internal energy of the gas will be:

Aicharya · Accepted Answer

For isobaric process and diatomic gas we can write, $Δ Q = n C_{P} Δ T = 735 J$

$\Rightarrow n \frac{7 R}{2} Δ T = 735 J \Rightarrow n R Δ T = 210$

Now internal energy will be,

$Δ U = n C_{V} Δ T = n \frac{5 R}{2} Δ T = \frac{5}{2} \times 210$

$= 525 J$

Heat energy of 735   J is given to a diatomic gas allowing the gas to expand at constant pressure. Each…

Solution

Heat energy of 735 &#160; J is given to a diatomic gas allowing the gas to expand at constant pressure. Each…

Solution

Heat energy of 735 J is given to a diatomic gas allowing the gas to expand at constant pressure. Each…