Heat energy is incident on the surface at the rate of $1000 \mathrm{~J} / \mathrm{min}$. If coefficient of…
Heat energy is incident on the surface at the rate of $1000 \mathrm{~J} / \mathrm{min}$. If coefficient of absorption is 0.8 and coefficient of reflection is 0.1 , then heat energy transmitted by the surface in 5 minute is
700 J
500 J
100 J
900 J
Solution
Considering energy conservation:
Coe. of transmission +Coe. of absorption +Coe. of reflection $=1$
Therefore, Coefficient of transmission $=1-0.8-0.1=0.1$
It means $10 \%$ of incident energy will be transmitted.
Hence transmitted energy in $5 \mathrm{~min}$
$=1000 \times 0.1 \times 5=500 \mathrm{~J}$