Heat energy absorbed by a system going through the cyclic process shown in the figure is

Heat energy absorbed by a system going through the cyclic process shown in the figure is
  1. $10^7 \pi \mathrm{~J}$
  2. $10^4 \pi \mathrm{~J}$
  3. $10^2 \pi \mathrm{~J}$
  4. $10^{-3} \pi \mathrm{~J}$

Solution

For cyclic process, $\begin{aligned} & \mathrm{Q}=\mathrm{W}=\text { Area of } \mathrm{p} \text {-v diagram } \\ & =\frac{\pi}{4} \times 20 \times 10^3 \times 20 \times 10^{-3}=10^2 \pi \mathrm{~J} \end{aligned}$

Asked in: AP EAMCET 2024 (21 May Shift 1)

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