Half mole of an ideal monoatomic gas is heated at a constant pressure of 1   atm from 20 °  …

Half mole of an ideal monoatomic gas is heated at a constant pressure of 1atm from 20° C to 90° C. Work done by the gas is(Gas constant,R=8.21 J mol-1 K-1)
  1. 73J
  2. 581J
  3. 291J
  4. 146J

Solution

Recall the formula of work done in terms of change in volume and pressure, in the case of isobaric process, where pressure is constant, W=PV2-PV1, now take the idea of ideal gas equation, 
W=nRT2-nRT1=12×8.3170=291 J

Asked in: JEE Main 2019 (10 Jan Shift 2)

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