Half-life period of a first order reaction is $1386 \mathrm{~s}$. The specific rate constant of the reaction…
Half-life period of a first order reaction is $1386 \mathrm{~s}$. The specific rate constant of the reaction is
- $5.0 \times 10^{-3} \mathrm{~s}^{-1}$
- $0.5 \times 10^{-2} \mathrm{~s}^{-1}$
- $0.5 \times 10^{-3} \mathrm{~s}^{-1}$
- $5.0 \times 10^{-2} \mathrm{~s}^{-1}$
Solution
Specific rate constant, $\mathrm{k}=\frac{0.693}{\mathrm{t}_{1 / 2}}=\frac{0.693}{1386}$
$=0.5 \times 10^{-3} \mathrm{~s}^{-1}$
Asked in: NEET 2009 (Screening)
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