Half life of a first order reaction is 1 hour. What fraction of it will remain after 3 hour?
- $\frac{1}{8}$
- $\frac{1}{9}$
- $\frac{1}{16}$
- $\frac{1}{64}$
Solution

$\because \quad$ Half life $\left(\mathrm{t}_{1 / 2}\right)=1$ hour $\therefore \quad$ Fraction available after 3 hours $=3 \times \mathrm{t}_{1 / 2}=\frac{1}{8}$
Asked in: MHT CET 2024 (04 May Shift 1)