Group- 13 elements react with O 2 in amorphous form to form oxides of type M 2 O 3 ( M = element). Which…

The basicity of an oxide is closely related to the electropositive character of the element. The more electropositive the element, the more basic its oxide will be. This is because the oxide ion can react with a cation to form a basic oxide. As we move down Group $13$, the electropositive character of the elements increases, and so does the basicity of their oxides.

${\mathrm{B}}_2{\mathrm{O}}_3<{\mathrm{Al}}_2{\mathrm{O}}_3<{\mathrm{Ga}}_2{\mathrm{O}}_3<{\mathrm{In}}_2{\mathrm{O}}_3<{\mathrm{Tl}}_2{\mathrm{O}}_3$

So most basic oxide among the given options is ${\mathrm{Tl}}_2{\mathrm{O}}_3$.