Glucose-D has a great tendency to be converted into cyclic isomer. Which two carbon atoms get joined through…
Glucose-D has a great tendency to be converted into cyclic isomer. Which two carbon atoms get joined through ' $\mathrm{O}$ ' to form this hemiacetal ?
$\mathrm{C}_{1}$ and $\mathrm{C}_{4}$
$\mathrm{C}_{1}$ and $\mathrm{C}_{5}$
$\mathrm{C}_{1}$ and $\mathrm{C}_{6}$
$\mathrm{C}_{2}$ and $\mathrm{C}_{6}$
Solution
Glucose exists as glucopyranose (a six membered ring structure) which is formed through $\mathrm{C}_{1}$ and $\mathrm{C}_{5}$.
.