Glucose and gluconic acid on oxidation with dilute nitric acid forms saccharic acid. This reaction confirms…
- four primary alcoholic groups
- two primary alcoholic groups
- one primary alcoholic groups
- five hydroxyl groups
Solution
Only one $-\mathrm{CH}_2-\mathrm{OH}$ convert into $-\mathrm{COOH}$, confirm presence of one primary alcoholic.Asked in: MHT CET 2021 (20 Sep Shift 1)