Given: C o 3 + + e - → C o 2 + ; E ° = + 1.81 V P b 3 + + 2 e - → P b 2 + ; E ° = + 1…

Given:
Co3++e-Co2+;E°=+1.81V
Pb3++2e-Pb2+;E°=+1.67V
Ce4++e-Ce3+;E°=+1.61V
Bi3++3e-Bi;E°=+0.20V
Oxidizing power of the species will increase in the order:
  1. Co3+<Ce4+<Bi3+<Pb4+
  2. Bi3+<Ce4+<Pb4+<Co3+
  3. Co3+<Pb4+<Ce3+<Bi4+
  4. Ce4+<Pb4+<Bi3+<Co3+

Solution

Higher the value of ERed0; higher will be its oxidizing power.

Hence correct order is Bi+3<Ce+4<Pb+4<Co+3

Asked in: JEE Main 2019 (12 Apr Shift 1)

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