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Given three vectors \(\mathbf{a}=2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}},…
Given three vectors \(\mathbf{a}=2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}}, \mathbf{b}=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}}\) and \(\mathbf{c}=\hat{\mathbf{i}}+\hat{\mathbf{j}}-2 \hat{\mathbf{k}}\), a vector in the plane of \(\mathbf{b}\) and \(\mathbf{c}\) whose projection on \(\mathbf{a}\) is of magnitude \(\sqrt{\frac{2}{3}}\) is
\(-2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+5 \hat{\mathbf{k}}\) \(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+3 \hat{\mathbf{k}}\) \(2 \hat{\mathbf{i}}+\hat{\mathbf{j}}+5 \hat{\mathbf{k}}\) \(2 \hat{\mathbf{i}}-3 \hat{\mathbf{j}}+3 \hat{\mathbf{k}}\)
Solution
Given three vectors are
\(\begin{aligned}
\mathbf{a} & =2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}}, \mathbf{b}=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}} \\
\text {and } \quad \mathbf{c} & =\hat{\mathbf{i}}+\hat{\mathbf{j}}-2 \hat{\mathbf{k}}
\end{aligned}\)
Now, let a vector in plane of \(\mathbf{b}\) and \(\mathbf{c}\) is
\(\begin{aligned}
\mathbf{d} & =\mathbf{b}+\lambda \mathbf{c} \\
& =(1+\lambda) \hat{\mathbf{i}}+(2+\lambda) \hat{\mathbf{j}}-(1+2 \lambda) \hat{\mathbf{k}}
\end{aligned}\)
\(\because\) Projection of vectord on a is \(=\sqrt{\frac{2}{3}}\)
\(\begin{aligned}
& \Rightarrow \quad \frac{\mathbf{d} \cdot \mathbf{a}}{|\mathbf{a}|}=\sqrt{\frac{2}{3}} \\
& \Rightarrow \quad \frac{2(1+\lambda)-(2+\lambda)-(1+2 \lambda)}{\sqrt{4+1+1}}=\sqrt{\frac{2}{3}} \\
& \Rightarrow \quad 2+2 \lambda-2-\lambda-1-2 \lambda=2 \\
& \Rightarrow \quad \lambda=-3
\end{aligned}\)
So, required vector \(\mathbf{d}=-2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+5 \hat{\mathbf{k}}\) Hence, option (a) is correct.
Asked in: AP EAMCET 2019 (23 Apr Shift 1)
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