Given three vectors \(\mathbf{a}=2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}},…

Given three vectors \(\mathbf{a}=2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}}, \mathbf{b}=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}}\) and \(\mathbf{c}=\hat{\mathbf{i}}+\hat{\mathbf{j}}-2 \hat{\mathbf{k}}\), a vector in the plane of \(\mathbf{b}\) and \(\mathbf{c}\) whose projection on \(\mathbf{a}\) is of magnitude \(\sqrt{\frac{2}{3}}\) is
  1. \(-2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+5 \hat{\mathbf{k}}\)
  2. \(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+3 \hat{\mathbf{k}}\)
  3. \(2 \hat{\mathbf{i}}+\hat{\mathbf{j}}+5 \hat{\mathbf{k}}\)
  4. \(2 \hat{\mathbf{i}}-3 \hat{\mathbf{j}}+3 \hat{\mathbf{k}}\)

Solution

Given three vectors are \(\begin{aligned} \mathbf{a} & =2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+\hat{\mathbf{k}}, \mathbf{b}=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}} \\ \text {and } \quad \mathbf{c} & =\hat{\mathbf{i}}+\hat{\mathbf{j}}-2 \hat{\mathbf{k}} \end{aligned}\) Now, let a vector in plane of \(\mathbf{b}\) and \(\mathbf{c}\) is \(\begin{aligned} \mathbf{d} & =\mathbf{b}+\lambda \mathbf{c} \\ & =(1+\lambda) \hat{\mathbf{i}}+(2+\lambda) \hat{\mathbf{j}}-(1+2 \lambda) \hat{\mathbf{k}} \end{aligned}\) \(\because\) Projection of vectord on a is \(=\sqrt{\frac{2}{3}}\) \(\begin{aligned} & \Rightarrow \quad \frac{\mathbf{d} \cdot \mathbf{a}}{|\mathbf{a}|}=\sqrt{\frac{2}{3}} \\ & \Rightarrow \quad \frac{2(1+\lambda)-(2+\lambda)-(1+2 \lambda)}{\sqrt{4+1+1}}=\sqrt{\frac{2}{3}} \\ & \Rightarrow \quad 2+2 \lambda-2-\lambda-1-2 \lambda=2 \\ & \Rightarrow \quad \lambda=-3 \end{aligned}\) So, required vector \(\mathbf{d}=-2 \hat{\mathbf{i}}-\hat{\mathbf{j}}+5 \hat{\mathbf{k}}\) Hence, option (a) is correct.

Asked in: AP EAMCET 2019 (23 Apr Shift 1)

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