Given the reaction between two gases represented by $A_2$ and $B_2$ to give the compound $A B(g)$.…

Given the reaction between two gases represented by $A_2$ and $B_2$ to give the compound $A B(g)$. $A_2(g)+B_2(g) \rightleftharpoons 2 A B(g)$ At equilibrium, the concentration of $A_2=3.0 \times 10^{-3} \mathrm{M}$ of $B_2=4.2 \times 10^{-3} \mathrm{M}$ of $A B=2.8 \times 10^{-3} \mathrm{M}$ If the reaction takes place in a sealed vessel at $527^{\circ} \mathrm{C}$, then the value of $K_c$ will be
  1. 2.0
  2. 1.9
  3. 0.62
  4. 4.5

Solution

$A_2(g)+B_2(g) \rightleftharpoons 2 A B(g)$ The equilibrium constant is given by $\begin{aligned} K_c=\frac{[A B]^2}{\left[A_2\right]\left[B_2\right]} & =\frac{\left(2.8 \times 10^{-3}\right)^2}{\left(3.0 \times 10^{-3}\right)\left(4.2 \times 10^{-3}\right)} \\ & =\frac{7.84}{12.6} \\ & =0.62 \end{aligned}$

Asked in: NEET 2012 (Mains)

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