The compound (s), which on reaction with \(\mathrm{HNO}_3\) will give the product having degree of rotation, \([\alpha]_{\mathrm{D}}=-52.7^{\circ}\) is (are)Given: The compound (s), which on reaction with \(\mathrm{HNO}_3\) will give the product having degree of…
The compound (s), which on reaction with \(\mathrm{HNO}_3\) will give the product having degree of rotation, \([\alpha]_{\mathrm{D}}=-52.7^{\circ}\) is (are)
Solution
Now the structure, that shows $[\propto]_{D}=-52.7^{\circ}$ is
Asked in: JEE Advanced 2021 (Paper 1)