Given that total of 16 values is 528 and sum of the squares of deviation from 33 is 9158. The variance is

Given that total of 16 values is 528 and sum of the squares of deviation from 33 is 9158. The variance is
  1. 562.73
  2. 570.375
  3. 574.375
  4. 572.375

Solution

We have $\mathrm{n}=16, \Sigma \mathrm{x}_{\mathrm{i}}=528$, and $\frac{528}{16}=33$ $\Rightarrow \overline{\mathrm{x}}=33$ and $\Sigma\left(\mathrm{x}_{\mathrm{i}}-\overline{\mathrm{x}}\right)^2=9158$ Variance $=\frac{1}{\mathrm{n}} \Sigma\left(\mathrm{x}_{\mathrm{i}}-\overline{\mathrm{x}}\right)^2=\frac{9158}{16}=572.375$

Asked in: MHT CET 2021 (23 Sep Shift 2)

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