Given, $CH_{3}COOH_{aq} \rightarrow CH_{3}COO^{-}_{aq} + H^{+}_{aq}$ $\Delta H_{rxn}^{o} = 0.004 \, kcal \, gm^{-1}$ Enthalpy change when $1$ mole of $Ba(OH)_{2}$, a strong base, is completely neutralized by $CH_{3}COOH(aq)$ is ($\Delta H^{\circ}$ of neutralization of strong acid with strong base…

Question

Given, $CH_{3}COOH_{aq} \rightarrow CH_{3}COO^{-}_{aq} + H^{+}_{aq}$ $\Delta H_{rxn}^{o} = 0.004 \, kcal \, gm^{-1}$ Enthalpy change when $1$ mole of $Ba(OH)_{2}$, a strong base, is completely neutralized by $CH_{3}COOH(aq)$ is ($\Delta H^{\circ}$ of neutralization of strong acid with strong base is $= -13.7 \, kcal \, mol^{-1}$)

Aicharya · Accepted Answer

ΔH o ionisaton of CH 3 COOH = 0 .04 × 60 = 0 .24 kcal/mol ∴ Enthalpy change = – 13.7 + 0.24 × 2 = − 26 .92 kcal mol − 1

Given, $CH_{3}COOH_{aq} \rightarrow CH_{3}COO^{-}_{aq} + H^{+}_{aq}$ $\Delta H_{rxn}^{o} = 0.004 \, kcal \,…

Solution