Given : $\mathrm{XNa}_{2} \mathrm{HAsO}_{3}+\mathrm{YNaBrO}_{3}+\mathrm{ZHCl} ightarrow…
The values of $X, Y$ and $Z$ in the above redox reaction are respectively :
- $2,1,2$
- $2,1,3$
- $3,1,6$
- $3,1,4$
Solution
$3 \mathrm{Na}_{2} \mathrm{HAsO}_{3}+\mathrm{NaBrO}_{3}+6 \mathrm{HCl} \longrightarrow 6 \mathrm{NaCl}+3 \mathrm{H}_{3} \mathrm{AsO}_{4}+\mathrm{NaBr}$
Asked in: JEE-TOPICTESTS-CHEMISTRY