Given below are two statements: Statement I: In the oxalic acid vs $\mathrm{KMnO}_4$ (in the presence of dil…
Statement I: In the oxalic acid vs $\mathrm{KMnO}_4$ (in the presence of dil $\mathrm{H}_2 \mathrm{SO}_4$) titration the solution needs to be heated initially to $60^{\circ} \mathrm{C}$, but no heating is required in Ferrous ammonium sulphate (FAS) vs $\mathrm{KMnO}_4$ titration (in the presence of dil $\mathrm{H}_2 \mathrm{SO}_4$)
Statement II: In oxalic acid vs $\mathrm{KMnO}_4$ titration, the initial formation of $\mathrm{MnSO}_4$ takes place at high temperature, which then acts as catalyst for further reaction. In the case of FAS vs $\mathrm{KMnO}_4$, heating oxidizes $\mathrm{Fe}^{2+}$ into $\mathrm{Fe}^{3+}$ by oxygen of air and error may be introduced in the experiment.
In the light of the above statements, choose the correct answer from the options given below
- Both Statement I and Statement II are false
- Both Statement I and Statement II are true
- Statement I is false but Statement II is true
- Statement I is true but Statement II is false
Solution
Heating is not required in FAS vs $\mathrm{KMnO}_4$ titration because $\mathrm{Fe}^{2+}$ will get converted into $\mathrm{Fe}^{3+}$ by oxygen of air and error may be introduced in the experiment.
Both Statement-I and Statement-II are correct.
Asked in: JEE Main 2025 (28 Jan Shift 1)