Given below are two statements. Statement I: Liquids A and B form a non-ideal solution with negative…
Given below are two statements.
Statement I: Liquids A and B form a non-ideal solution with negative deviation. The interactions between $A$ and B are weaker than $\mathrm{A}-\mathrm{A}$ and $\mathrm{B}-\mathrm{B}$ interactions
Statement II: In reverse osmosis, the applied pressure must be higher than the osmotic pressure of solution
The correct answer is
Both Statement-I and Statement-II are correct
Both Statement-I and Statement-II are not correct
Statement-I is correct but Statement-II is not correct
Statement-I is not correct but Statement-II is correct
Solution
In case of negative deviations from raoult's law, the intermolecular attractive forces between $\mathrm{A}-\mathrm{A}$ and $\mathrm{B}-\mathrm{B}$ are weaker than those between $A-B$ and leads to decrease in vapour pressure resulting in negative deviations.
In reverse osmosis the applied pressure must be higher than the osmotic pressure of solution.
Hence Statement I is incorrect but II is correct.