Given below are the pairs of group 13 element showing their relation in terms of atomic radius. $(\mathrm{B}…
$(\mathrm{B} \lt \mathrm{Al}),(\mathrm{Al} \lt \mathrm{Ga}),(\mathrm{Ga} \lt \mathrm{In}) \text { and }(\mathrm{In} \lt \mathrm{Tl})$
Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius $\left(\mathrm{M}^{3+}\right)$ that the other one. The atomic number of the element $(\mathrm{X})$ is
- 31
- 49
- 13
- 81
Solution
$\begin{aligned}
& \mathrm{Al} \gt \mathrm{Ga} \\
& \mathrm{Al}^{3+} \lt \mathrm{Ga}^{3+}
\end{aligned}$
Atomic number of Ga is 31
Asked in: JEE Main 2025 (04 Apr Shift 1)
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