Given below are the atomic numbers of some group 14 elements. The atomic number of the element with lowest…
- 6
- 82
- 14
- 50
Solution
$\begin{array}{ll}
\text { element } & \text { M.P. }\left({ }^{\circ} \mathrm{C}\right) \\
\mathrm{Z}=6=\mathrm{C} & 3730 \\
\mathrm{Z}=14=\mathrm{Si} & 1410 \\
\mathrm{Z}=32=\mathrm{Ge} & 937 \\
\mathrm{Z}=50=\mathrm{Sn} & 232 \\
\mathrm{Z}=82=\mathrm{Pb} & 327
\end{array}$
Asked in: JEE Main 2025 (23 Jan Shift 2)
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