Give the decreasing order of hyperconjugative effect of $\mathrm{R}$ in…

Give the decreasing order of hyperconjugative effect of $\mathrm{R}$ in $\mathrm{R}-\mathrm{CH}=\mathrm{CH}_{2}$, where $\mathrm{R}$ is:
I. $\mathrm{Me-}$
II. $\mathrm{Et-}$
III. $\mathrm{Me}_{2} \mathrm{CH}-$
IV. $\mathrm{Me}_{3} \mathrm{C}-$
  1. $\mathrm{I}>\mathrm{II}>\mathrm{III}>\mathrm{IV}$
  2. $\mathrm{IV}>\mathrm{III}>\mathrm{II}>\mathrm{I}$
  3. $\mathrm{II}>\mathrm{I}>\mathrm{II}>\mathrm{IV}$
  4. $\mathrm{IV}>\mathrm{III}>\mathrm{I}>\mathrm{II}$

Solution

The more number of alpha hydrogens, the more is the hyperconjugative effect. /

Asked in: JEE-TOPICTESTS-CHEMISTRY

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