General solution of the differential equation $\sin ^3 \mathrm{x} \frac{\mathrm{dx}}{\mathrm{dy}}=\sin…
General solution of the differential equation $\sin ^3 \mathrm{x} \frac{\mathrm{dx}}{\mathrm{dy}}=\sin \mathrm{y}$ is given by
- $\cos y-\frac{3}{4} \cos x-\frac{1}{12} \cos 3 x=C$
- $\cos y-\frac{3}{4} \cos x+\frac{1}{12} \cos 3 x=C$
- $\cos y+\frac{3}{4} \cos x-\frac{1}{12} \cos 3 x=C$
- $\cos y+\frac{3}{4} \cos x+\frac{1}{12} \cos 3 x=C$
Solution
$\begin{aligned} & \sin ^3 x \frac{d x}{d y}=\sin y \Rightarrow \int \sin ^3 x d x=\int \sin y d y \\ & \Rightarrow \int \frac{3 \sin x-\sin 3 x}{4} d x=\int \sin y d y \\ & \Rightarrow \frac{-3}{4} \cos x+\frac{1}{4} \cdot \frac{\cos 3 x}{3}=-\cos y+C \\ & \Rightarrow \cos y-\frac{3}{4} \cos x+\frac{1}{12} \cos 3 x=C\end{aligned}$
Asked in: MHT CET 2022 (05 Aug Shift 1)
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