General electronic configuration of lanthanides is:

Question

Aicharya · Accepted Answer

The general electronic configuration is $(n-2) f^{-14}(\mathrm{n}-1) \mathrm{d}^{0-1} n s^2$
Related Theory
$\begin{array}{|l|l|}
\hline \text { Element } & \begin{array}{l}
\text { General outer electronic configuration }
\end{array} \\
\hline s \text {-block } & n s^{l-2} \text {, wheren } n=2-7 \\
\hline \text { p-block } & n s^2 n p^{\prime 4}, \text { wheren } n=2-6 \\
\hline \text { d-block } & \begin{array}{l}
(n-l) d^{1-10}, n s^{0-2} \text {, where } n= 4-7
\end{array} \\
\hline \text { f-block } & \begin{array}{l}
(n-2) f^{1-14}(n-l) ~d^{n-1} ~f^{f-14} ~n s^2, \\
\text { where } n=6-7
\end{array} \\
\hline
\end{array}$

General electronic configuration of lanthanides is:

Solution