$f(x)=|\log_{e} x|$ is differentiable at
- \(x=0\) only
- \(x=1\) only
- \(x=-1\) only
- \(R-\{0, \pm 1\}\)
Solution

Hence, option (d) is correct.
Asked in: AP EAMCET 2020 (21 Sep Shift 2)
Practice more Continuity and Differentiability questions on Aicharya

Asked in: AP EAMCET 2020 (21 Sep Shift 2)
Practice more Continuity and Differentiability questions on Aicharya