From the top of a 64 metres high tower, a stone is thrown upwards vertically with the velocity of 48  …

From the top of a 64 metres high tower, a stone is thrown upwards vertically with the velocity of 48 m/s. The greatest height (in metres) attained by the stone, assuming the value of the gravitational acceleration g=32 m/s2, is:
  1. 112
  2. 88
  3. 128
  4. 100

Solution

We know that v2=u2+2gs.

At greatest height v=0

u=48 m/sec

g=-32 m/sec2

S=48×482.32=36 m

Total distance =64 m+36 m=100 m

=100 m

Asked in: JEE Main 2015 (11 Apr Online)

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