From the given data, the amount of energy required to break the nucleus of aluminium ${}_{13}^{27}{Al}$ is __________ $x \times 10^{- 3} J$
Mass of neutron $= 1.00866 u$
Mass of proton $= 1.00726 u$
Mass of Aluminium nucleus $= 27.18846 u$
(Assume $1 u$ corresponds to $x J$ of energy)
(Round off to the nearest integer)

Question

From the given data, the amount of energy required to break the nucleus of aluminium ${}_{13}^{27}{Al}$ is __________ $x \times 10^{- 3} J$

Mass of neutron $= 1.00866 u$
Mass of proton $= 1.00726 u$
Mass of Aluminium nucleus $= 27.18846 u$
(Assume $1 u$ corresponds to $x J$ of energy)
(Round off to the nearest integer)

Aicharya · Accepted Answer

&#916; m = Z m P + ( A - Z ) m n - M Al = ( 13 &#215; 1 . 00726 + 14 &#215; 1 . 00866 ) - 27 . 18846 = 27 . 21562 - 27 . 18846 = 0 . 02716 &#160; u E = 27 . 16 x &#215; 10 - 3 &#160; J

From the given data, the amount of energy required to break the nucleus of aluminium Al 13 27 is __________…

Solution