From all the English alphabets, five letters are chosen and are arranged in alphabetical order. The total…
- $5148$
- $6084$
- $4356$
- $14950$
Solution
& \underbrace{A B}_{12} \quad \underbrace{\text { MN........Z }}_{13} \\ & =\underset{\substack{\text { Selection of two } \\ \text { leters before } \mathrm{M}}}{{ }^{12} \mathrm{C}_2} \times \underset{\substack{\text { Selection of two } \\ \text { leter after } \mathrm{M}}}{{ }^{13} \mathrm{C}_2}=5148
\end{aligned}$ ,
Asked in: JEE Main 2025 (22 Jan Shift 1)