From a uniform solid cone of base radius $R$ and height $H$ , a symmetric cone of the base radius $\frac{R}{2}$ is removed as shown. Then the centre of mass is shifted by $\frac{H}{n} .$ Find the value of $n$ .

Question

From a uniform solid cone of base radius R and height H , a symmetric cone of the base radius R 2 is removed as shown. Then the centre of mass is shifted by H n . Find the value of n .

Aicharya · Accepted Answer

y C O M = m 1 y 1 - m 2 y 2 m 1 - m 2 = M . H 4 - M 8 H 8 M - M 8 = 15 H 56 Δ y = 15 H 56 - H 4 = H 56

From a uniform solid cone of base radius R and height H , a symmetric cone of the base radius R 2 is removed…

Solution